Question

In a H-W population of 250 individuals, the recessive and the homozygous dominant
individuals are 30% and 20% respectively. Then the recessive allele frequency in that
population is
1) 0.42
2) 0.55
3) 0.48
4) 0.05

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Answer 1

Answer:

hii dude

Explanation:

2)0.55

because wahi hoga

Answer 2

Answer:

The frequency of the recessive allele is 1) 0.42

Explanation:

Hardy and Weinberg, independently discovered a rule that relates allelic and genotypic frequencies in a Mendelian population. One of the rules states that the genotypic frequencies of the population are determined in a predictable way by the allelic frequencies (genotypic-frequency equilibrium). If the allele frequencies in a population with two alleles at a locus are p and q then the expected genotypic frequencies are $p^{2}$, $2$$pq$ and $q^{2}$

According to the question, the frequency of recessive allele for a certain hereditary trait:

∴ $q^{2}$= (30/250)

or, $q^{2}$= 0.12

or, $q$ =$\sqrt{0.12}$

or, $q$ = 0.34

According to the question, the frequency of the dominant allele for a certain hereditary trait:

∴ $p^{2}$ = (20/250)

or, $p^{2}$ = 0.08

or, $p$ = $\sqrt{0.08}$

or, $p$ = 0.28

The frequency of heterozygous genotype in the population

∴ $2pq$ =2x0.28x0.34 = 0.19

∴ The frequency of the recessive allele = 0.34 + (1/2)0.19=0.43

So, the correct option will be 1)