Question

In a half hour, a 65 kg jogger can generate 8.0x10 5 J of heat. This heat is removed from the jogger’s body by a variety of means, including the body’s own temperature regulating mechanisms. If the heat were not removed, how much would the jogger’s body temperature increase?

Answer 1

Answer:

what the question

Answer 2

Given - Mass of jogger - 65 kg

Heat generated - 8.0*10⁵ J

Find - Increase in body temperature of jogger.

Solution - Increase in body temperature can be calculated by the following formula - Q = m*c*∆t, where Q is heat, m is mass of body, c is specific heat capacity and ∆t is change in temperature.

Specific heat capacity of human body = 3500 J/kg °C.

Keeping the values in equation-

∆t = Q/m*c

∆t = 8*10⁵/(65*3500)

∆t = 3.5 °C

Therefore, the increase in body temperature would be 3.5 °C.