In a Harbour, wind is blowing at a speed of 72 km/hb and the flag on the mast of a boat anchored in the harbour flutters along the N-E direction. If a boat start moving at the speed of 51 km/h to the north, what is the direction of the flag on mast of a boat?
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Answer:
Explanation:
The flag is fluttering in the north-east direction. It shows that the wind is blowing toward the north-east direction. When the ship begins sailing toward the north, the flag will move along the direction of the relative velocity (v
wb
) of the wind with respect to the boat.
The angle between v
w
and v
b
=90+45
tanθ=
(72+51cos(90+45)
51sin(90+45)
Substituting and solving we get,
tanθ=
50.80
51
=1.0038
θ=tan
−1
(1.0038)=45.11
0
Angle with respect to the east direction = 45.11−45=0.11
Hence, the flag will flutter almost due east.
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