Question

In a harbour ,wind is blowing at the speed of 72km/h and the flag on the mast of a boat anchored in the harbour flutters along the N-E direction.If the boat starts moving at a speed of 51 km/h to the North,what is the direction of the flag on the mast of the boat?



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Answer 1

Answer:The flag is fluttering in the north-east direction. It shows that the wind is blowing toward the north-east direction. When the ship begins sailing toward the north, the flag will move along the direction of the relative velocity (vwb​) of the wind with respect to the boat.

The angle between vw​ and vb​  =90+45

  tanθ=(72+51cos(90+45)51sin(90+45)​

Substituting and solving we get,

tanθ=50.8051​=1.0038

θ=tan−1(1.0038)=45.110

Angle with respect to the east direction = 45.11−45=0.11

Hence, the flag will flutter almost due east.

Explanation:

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Answer 2

Answer:

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