Question

In a Hardy-Weinberg population, four people out of 100 express a recessive trait. Find the
probability that the offspring of two individuals who do not express the trait will express it.
a. 0.25
b. 0.20
c. 0.32
d. 0.026
Answer​

Answer 1

Answer:

0.25

Explanation:

Answer 2

Concept

A population's genetic variety will remain constant from one generation to the next if no unfavorable conditions arise, according to the Hardy-Weinberg equilibrium principle. Allele frequencies will remain constant over generations when a population is in Hardy-Weinberg equilibrium for a gene. There are five fundamental Hardy-Weinberg presumptions: absence of mutation, asexual reproduction, absence of gene flow, limitless population size, and absence of selection. A key tenet of population genetics is the Hardy-Weinberg Equilibrium (HWE), which asserts that "genotype frequencies in a population stay stable between generations in the absence of perturbation by outside causes."

Explanation

Probability of occurrence of homozygous recessive offspring from heterozygous parent is $1/4=0.25$.

Hence, probability that the offspring of two individuals who do not express the trait will express it is a. $0.25$.

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