in a hare totoise race the hare ran for 5 minutes at a speed of 5km/h , slept for 50 minutes , and then ran for 5 minutes at a speed of 7.5km/h . what is the average speed of hare in the race?
Answers
Given data : In a hare-tortoise race the hare ran for 5 minutes at a speed of 5 km/hr , slept for 50 minutes , and then ran for 5 minutes at a speed of 7.5 km/hr.
To find : The average speed of hare in the race ?
Solution :
Here, 5 minute = 5/60 hour = 1/12 hour.
First case :
⟹1'st speed = 5 km/hr
⟹ 1'st time = 1/12 hr
⟹ 1'st distance = ?
Now by formula of speed :
⟹ speed = distance/time
⟹ 5 = distance/{1/12}
⟹ distance = 5 * 1/12
⟹ distance = 5/12 km
∴ 1'st distance = 5/12 km
Second case :
⟹ 2'cd speed = 7.5 km/hr
⟹ 2'cd time = 5/12 hr
⟹ 2'cd distance = ?
Now by formula of speed :
⟹ speed = distance/time
⟹ 7.5 = distance/{1/12}
⟹ distance = 7.5 * 1/12
⟹ distance = 7.5/12
⟹ distance = 5/8 km
∴ 2'cd distance = 5/8 km
Now,
⟹ Total distance covered by hare-tortoise = 1'st distance + 2'cd distance
⟹ Total distance covered by hare-tortoise = 5/12 + 5/8
⟹ Total distance covered by hare-tortoise = (5*8)/(12*8) + (5*12)/(8*12)
⟹ Total distance covered by hare-tortoise = 40/96 + 60/96
⟹ Total distance covered by hare-tortoise = 100/96
⟹ Total distance covered by hare-tortoise = 25/24 km
Now,
⟹ Total time taken by hare-tortoise = 1'st time + 2'cd time + slept time
⟹ Total time taken by hare-tortoise = {5 + 5 + 50 } minute
⟹ Total time taken by hare-tortoise = 60 minute
⟹ Total time taken by hare-tortoise = 1 hour
Now,
⟹ average speed = total distance/total time taken
⟹ average speed = 25/24 /( 1 )
⟹ average speed = 25/24
⟹ average speed = 1.041666667 km/hr
Answer : Hence, average speed of hare in the race is 1.041666667 km/hr.
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