Question

in a harmonic progression 4/3,3/2,12/7,... find 7th term?

Answer 1

4/3,3/2,12/7...... are in HP

so,
3/4, 2/3, 7/12....., are in AP

first term =3/4
common difference =-1/12
tn=a+(n-1)d

t7 =3/4+(7-1)(-1/12)
=3/4-1/2=1/4
hence ,
7th term in GP =4

Answer 2

Answer:

Step-by-step explanation:

4/3,3/2,12/7,............are in HP

So,

3/4,2/3,7/12,............are in AP

(according to the rule)

First term =3/4

Common difference =-1/12

(formula =

tn=a+(n-1)d. )

t7=3/4+(7-1)(-1/12)

=3/4-1/2=1/4

Hence,

The terms of the hp4/3,3/2,12/7,....is "4

HOPE IT HELPS........... ............