in a heatengine the temperature of the source and sink 700°c and50°c respectively the heat supplied 5mj/min what is maximum efficiency by the engine
Answers
Answered by
0
Answer:
Given,
T1=500K
T2=375K
Q1=25×105J
Efficiency of the engine,
η=1−T1T2
η=1−500375
η=1−0.75
η=0.25=25%
We know that, η=Q1W
W=ηQ1
W=0.25×25×105
W=6.25×105J
The correct option is A.
Answered by
0
Answer:
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Explanation:
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