In a hexagon ABCDEF, side AB is parallel to side FE and angleB:angleC:angleD:angleE=6:4:2:3
FIND angleB and angleD.
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Answered by
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As AB || FE, FA becomes the tranversal line cutting parallel lines. So angle A + angle F = 180°.
sum of other four angles = 720° - 180°= 540°.
So 6 x + 4 x + 2 x + 3 x = 15 x = 540°.
x = 36°.
Angles B C D E are: 216°, 144°, 72°, 108°
sum of other four angles = 720° - 180°= 540°.
So 6 x + 4 x + 2 x + 3 x = 15 x = 540°.
x = 36°.
Angles B C D E are: 216°, 144°, 72°, 108°
kvnmurty:
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