In a hockey tournament there are 12 teams, divided in 2 groups. Each group has 6 teams. Teams of each group will play once against each other. From each group, 4 top teams will qualify for the second round. In the second round each team will play against every other team in its group once. 4 top teams of second round will qualify for the semifinal round, where they will play against each other once. Top 2 teams will proceed to final. The final will be played in the form of best of three matches. The minimum and maximum number of matches in this tournament will respectively be:
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Answer:THE MAXIMUM NUMBER OF MATCHES IN THIS TOURNAMENT WILL BE 99.
Step-by-step explanation:GIVEN:-THERE ARE 12 TEAMS.
EACH GROUP HAS 6 TEAMS.TEAMS OF EACH GROUP WILL PLAY ONCE AGAINST EACH OTHER .
ONE TEAM WILL PLAY 5 MATCHES IN THE FIRST ROUND=12*5=60.
FROM THE EACH GROUP 4 TOP TEAMS WILL QUALIFY FOR THE SECOND ROUND.IN THE SECOND ROUND EACH TEAM WILL PLAY AGAINST EVERY OTHER TEAM IN ITS GROUP ONCE.
EACH TEAM WILL PLAY 3 MATCHES IN THE SECOND ROUND=3*8=24.
4 TOP TEAMS OF SECOND ROUND WILL QUALIFY FOR SEMIFINAL ROUND.THERE EACH TEAM WILL PLAY ONCE AGAINST EACH OTHER.
ONE TEAM WILL PLAY 3 MATCHES AGAINST EACH OTHER=3*4=12.
TOP 2 TEAMS WILL PROCEED TO FINAL. THE FINAL WILL BE PLAYED IN THE FORM OF OF BEST OF THREE MATCHES.
BOTH THE TEAMS WILL PLAY THREE MATCHES AGAINST EACH OTHER.
THE MAXIMUM NUMBER OF MATCHES PLAYED IN THE TOURNAMENT= 60+24+12+3=99.
THE MINIMUM MATCHES PLAYED IN THE TOURNAMENT BY A TEAM =5
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Step-by-step explanation:
12 teams divided into 2 groups and using permutations and combinations we get 47 maximum and 15 minimum tournaments
final answer is 47, 15
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