Question

in a homozygous pea plant axial flowers(A)are dominant over terminal flower(a)

i)what is the phenotype and genotype of f1 generation if plant bearing pure axial flower is crossed with a plant bearing pure terminal flower
ii)draw the punnett square board to show the gamet and offsprings when both the parent plants are hetorozygous for axial flower
iii)phenotypic ratio and genotypic ratio of above cross shown in(ii)

Answer 1

Answer:

Explanation:

Answer for your question is given in the attachment. Hope it helps..

Answer 2

Answer:

Homozygous pea plant axial flowers A is crossed to Terminal flowers recessive a.

Explanation:

i. Phenotype= Axial flowers

Genotype= Aa

ii. When Aa is crossed with Aa then the gametes A, a, A and a generate new offsprings as AA, Aa, Aa, and aa, therefore 3 axial flowers and 1 terminal flower will be generated.

Please find the cross attached.

iii. Phenotypic ratio= 3:1 i.e., 3 axial flowers and 1 terminal flower.

Genotypic ratio= 1:2:1