Question

In a horse race there were 18 horses numbered 1-18. The probability that horse 1 would win is 1/6, that 2 would win is 1/10 and that 3 would win is 1/8. Assuming that a tie is impossible, find the change that one of the three will win

47/120
117/120
11/129
43105

Answer 1

Your answer is 47/120
1/6+1/8+1/10=47/120

Answer 2

Answer:

answer is 47/120

Step-by-step explanation:

here we have to focus only on the three horses 1,2,3.

the probability of their winning is 1/6, 1/10, 1/8 for [1,2,3 respectively]

now the question reduces to simply that 1wins OR 2wins OR 3wins because a tie is never possible.

answer. 1/6 + 1/10 + 1/8 = 47/120