In a horse racing competition there were 18 numbered 1 to 18.the organisers assigned a probablity of winning the race to each horse such that horse1 would win is 1/7,for horse 2 it is 1/8 and for horse 3 it is 1/8.Assuming that tie is not possible.find chance that one of these three will win the race???
ans-23/56; In a horse racing competition there were 18 numbered 1 to 18.the organisers assigned a probablity of winning the race to each horse such that horse1 would win is 1/7,for horse 2 it is 1/8 and for horse 3 it is 1/8.Assuming that tie is not possible.find chance that one of these three will win the race???; ans-23/56
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for the first question you just need to add all the probabilities
that is 1/8 + 1/8 +1/7 = 8+7+7/56 = 24 / 56 = 3/7
plz mark as brainliest .... it will help a lot plz
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