In a hostel there are 125 students ,out of which 80 drinks tea, 60 drink coffee and 20 drink tea and coffee both. find
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Answer:
let tea be A
let coffee be B
then
n(AUB) = n(A)+n(B)-n(A^B)
= 80+60-20
= 120
so 120 students drink both tea or coffee or both
and 5 students drink neither tea or cofee
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