Question

In a hot water heater system, there is a cyclinderical pipe of length 35cm and diameter 10cm find its total radiating system

Answer 1

Step-by-step explanation:

Given that: In a hot water heater system, there is a cylinderical pipe of length 35cm and diameter 10cm

To find: Total radiating surface

Solution: Total radiating surface of cylinderical pipe is curved surface area of cylinder.

$\boxed{\bold{CSA\:of\:cylinder=2\pi\:rh\: unit^{2}}}$

Here,

h;l= length of pipe= 35 cm

Diameter of pipe=10 cm

Radius r= 5 cm

$CSA\:of\: cylinderical\: pipe=2\times\frac{22}{7}\times5\times35\:\: cm^{2}\\\\CSA\:of\: cylinderical\: pipe=2\times22\times5\times5\\\\=44\times25\\\\CSA\:of\: cylinderical\: pipe=1100 cm^2$

Total radiating surface of pipe is 1100 sq-cm.

Hope it helps you.