Question

in a hot water heating system , there is a cylindrical pipe of length 28 m and diameter 5 cm . find the total radiating surface in the system

Answer 1

Given length  = 28 m.

           diameter = 5 cm then the radius will be r = 5/2 cm = 0.025m.

Total Radiating Surface in the system = 2pirh

                                                                = 2 * 22/7 * 0.025* 28

                                                                = 4.4 m^2.


Hope this helps!

Answer 2

Answer:

Step-by-step explanation:

Given Length =28m

Diameter = 5/2cm = 0.025. (When we divide it by 2 and then by 100)

Then the radius will be radius = 5/2cm = 0.025

Total radiating Surface in the System = 2πrh

2×22/7×0.025×28

= 4.4m²

Hope You Understand..!