Question

in a hot water heating system there is a cylindrical pipe of length 28 m and diameter 5cm find the total radiating surface in the system

Answer 1

Surface area =2πr(r+h) 

R=   5/2 =2.5

H=28

Area=2*π*2.5*(2.5+28)

=478.85

Answer 2

$\huge\star\mathfrak\purple{{HEY MATE....!!}}$

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✴.Radius[R] = $\frac{diameter}{2} ={5}{2}$ =2.5Cm.

Length of the pipe = height =14m

Radiating surface = 2${\phi}$ rh

2${\phi}$ $\frac{22}{7}$ × 2.5 × 28

=478.85${cm}^3$

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