In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system
Answers
Answered by
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Step-by-step explanation:
Given :- a cylindrical water heating system of lenght 28 m and diameter 5 cm
To find out = radiating surface area
Solution:-
As we know that total surface area is the radiating area here
so height is 28m
and radius is 5/2cm
=> tsa of cylinder => 2pir(r+h)
=> 2×22/7×5/2(5/2+2800)
28m = 2800 cm
=> 110/7×2802.5
=> 110/7×28025/10
=> 11×4003
=> 44033 cm² approximately
Answered by
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Step-by-step explanation:
Given:
the height as h: 28m or 2800cm
radius as r : 5cm/2 = 2,5cm
csa of a cylinder = 2πrh
=> 2*22/7*2.5*2800
=>44/7*7000
=>44 * 1000
=>44000cm²
=>4.4m²
thus the total radiating surface is 4.4 m²
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