Question

In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system

Answer 1

Step-by-step explanation:

Given :- a cylindrical water heating system of lenght 28 m and diameter 5 cm

To find out = radiating surface area

Solution:-

As we know that total surface area is the radiating area here

so height is 28m

and radius is 5/2cm

=> tsa of cylinder => 2pir(r+h)

=> 2×22/7×5/2(5/2+2800)

28m = 2800 cm

=> 110/7×2802.5

=> 110/7×28025/10

=> 11×4003

=> 44033 cm² approximately

Answer 2

Step-by-step explanation:

Given:

the height as h: 28m or 2800cm

radius as r : 5cm/2 = 2,5cm

csa of a cylinder = 2πrh

=> 2*22/7*2.5*2800

=>44/7*7000

=>44 * 1000

=>44000cm²

=>4.4m²

thus the total radiating surface is 4.4 m²