Question

In a hot water heating system there is a cylindrical pipe of length 28m and diameter 5cm . The total radiating surface area in the system in m^2 is.... a. 6.6 b. 5.5 c. 4.4 d. 3.4

Answer 1

Answer:

here's your answer dude

Answer 2

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h = 28m

2r=5cm

$\therefore$ r = $\large\dfrac{5}{2}$ cm = $\large\dfrac{5}{2×100}$

= $\large\dfrac{5}{200}$ m = $\large\dfrac{1}{40}$ m

$\therefore$ Total radiating surface in the system

= ${\small{\boxed{\sf{\pink{2πrh}}}}}$

= 2 × $\large\dfrac{27}{7}$ × $\large\dfrac{1}{40}$ × 28 = ${\underline{\underline{4.4m²}}}$

The area of the radiating surface of system is 4.4 m²

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