Question

in a hot water heating system there is a cylindrical pipe of length 28 cm and diameter 5 cm . Find the total radiating surface in the system.....please help me...​

Answer 1

$\bf{\underline{Question:-}}$

in a hot water heating system there is a cylindrical pipe of length 28 cm and diameter 5 cm . Find the total radiating surface in the system

$\bf{\underline{Given:-}}$

• length = 28 m.

• diameter = 5 cm
• then the radius will be r = 5/2 cm = 0.025m.

$\bf{\underline{Solution:-}}$

• Total Radiating Surface in the system = 2πrh

Substituting the value in formula

→ 2πrh

→ 2 × 22/7 × 0.025 × 28

→ 4.4 m²

$\bf{\underline{Hence:-}}$

• the total radiating surface in the system is 4.4 m²

Answer 2

$\huge\mathbb\pink{Hey \: Mate!!}$

${\huge{\red{\underline{\overline{\mathit{\red{ANSWER↓}}}}}}}$

h = 28m

2r=5cm

$\therefore$ r = $\large\dfrac{5}{2}$ cm = $\large\dfrac{5}{2×100}$

= $\large\dfrac{5}{200}$ m = $\large\dfrac{1}{40}$ m

$\therefore$ Total radiating surface in the system

= ${\small{\boxed{\sf{\pink{2πrh}}}}}$

= 2 × $\large\dfrac{27}{7}$ × $\large\dfrac{1}{40}$ × 28 = ${\underline{\underline{4.4m²}}}$

The area of the radiating surface of system is 4.4 m²

$\large\underline\mathbb\red{HOPE \: THIS \: HELPS \: U}$

$\large\fbox\colorbox{pink}{Mark \: as Brainliest}$