Math, asked by Aniketgupta17890, 5 months ago

In a hot water heating system, there is a cylindrical pipe of length 21 m and diameter 5 cm. Find the total radiating surface in the system.​

Answers

Answered by Anonymous
8

Answer:

Diameter = 5 cm

Radius = Diameter ÷2=5cm÷2=2.5cm

length of pipe =28m=2800cm

Total Radiating Surface of pipe = Curved surface area + 2 × Area of circular crossection

=2πrh+2πr

2

=2πr(h+r)=2×

7

22

×2.5(2800+2.5)=44039.28cm

2

Step-by-step explanation:

hope it's help you ☺️☺️

Answered by pyarkenaampardhoka
1

Step-by-step explanation:

44039.39 ans of your question

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