Question

in a hot water heating system there is a cylindrical pipe of lenght 28m and diameter 5 cm. find the total radiating surface area in the system in m

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Diameter = 5 cm

Diameter = 5 cmRadius = Diameter ÷2=5cm÷2=2.5cm

Diameter = 5 cmRadius = Diameter ÷2=5cm÷2=2.5cmlength of pipe =28m=2800cm

Diameter = 5 cmRadius = Diameter ÷2=5cm÷2=2.5cmlength of pipe =28m=2800cmTotal Radiating Surface of pipe = Curved surface area + 2 × Area of circular crossection

Diameter = 5 cmRadius = Diameter ÷2=5cm÷2=2.5cmlength of pipe =28m=2800cmTotal Radiating Surface of pipe = Curved surface area + 2 × Area of circular crossection=2πrh+2πr²=2πr(h+r)=2×22×2.5(2800+2.5)=

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=44039.28cm²