Question

In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter
5 cm. Find the total radiating surface in the system.​

Answer 1

Step-by-step explanation:

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Answer 2

The dimensions of cylindrical pipe

Diameter =5cm

Radius =5/2=2.5cm

Height =28m=2800cm

We know that,

Total radiating surface in the system = curved surface area of cylindrical pipe =2 πrh

By substituting the values

Total radiating surface in the system =2×(22/7)×2.5×2800

So we get,

Total radiating surface in the system =44000 cm²

Therefore , the total radiating surface in the system is 44000 cm²