Question

in a hot water heating system , there is a cylindrical pipe of length 28m and diameter 5cm. find the total radiating surface in the system?​

Answer 1

Answer:

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✯Given :-

Length of cylinder pipe = 28m

Radius of circular end of pipe = 5/2 cm = 2.5cm

$\tt r = 2.5 \times \frac{1}{100} m = 0.025m$

The cylindrical pipe radiates from curved surface and not from ends.

So , We have to find curved surface area of a cylinder

Total radiating surface in the system = CSA of a cylindrical pipe

$\tt = 2\pi \: rh$

$\tt = (2 \times \frac{22}{7} \times 0.025 \times 28) {m}^{2}$

$\tt = 4.4 \: {m}^{2}$

Therefore , total radiating surface in the system is

$\tt \red{ = 4.4 {m}^{2} }$