Question

. In a hot water heating system, there is a cylindrical pipe of length 2 mand diameter
5 cm Find the total radiating surface in the system​

Answer 1

Answer:

Given length = 28 m. diameter = 5 cm then the radius will be r = 5/2 cm = 0.025m. = 4.4 m^2. Hope this helps!

Answer 2

Given Length =28m  

Diameter = 5/2cm = 0.025. (When we divide it by 2 and then by 100)  

Then the radius will be radius = 5/2cm = 0.025  

Total radiating Surface in the System = 2πrh = 2×22/7×0.025×28 = 4.4m²

Hope it helped :)