In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.
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D
44039.28cm
2
Diameter = 5 cm
Radius = Diameter ÷2=5cm÷2=2.5cm
length of pipe =28m=2800cm
Total Radiating Surface of pipe = Curved surface area + 2 × Area of circular crossection
=2πrh+2πr
2
=2πr(h+r)=2×
7
22
×2.5(2800+2.5)=44039.28cm
2
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