Question

In a hot water heating system, there is a cylindrical pipe of length 35 m and diameter 5 cm. Find the total radiating surface in the system

Answer 1

Answer:

Solution

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Given:

H=28m, R=

2

5

=2.5cm =0.025m (

100

2.5

)

⇒CSA of pipe (cylindrical)=2πrh

=2×

7

22

×0.025×28m

2

=4.4m

2

Step-by-step explanation:

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