Question

in a hot water heating system there is a cylindrical pipe of length 35 M and radius 4 cm find the total radiating surface in the system​

Answer 1

Answer:

Dil Ki nhi Manara hoga minimum of two or three times a week or so and I say

Answer 2

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Diameter = 5 cm

Radius = Diameter ÷2=5cm÷2=2.5cm

length of pipe =28m=2800cm

Total Radiating Surface of pipe = Curved surface area + 2 × Area of circular crossection

=2πrh+2πr²

=2πr(h+r)=2×22/7

×2.5(2800+2.5)=44039.28cm²

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