Question

in a hot water heating system, there is a cylindrical pipe of length 28 m and diameter of 5 cm. Find the total radiating surface in the system ​

Answer 1

hope this helps mate..

Answer 2

Step-by-step explanation:

r= 5/2=2.5cm=0.025m

h=28m

total radiating surface of the system = total surface of the cylinder

=2×22/7×r(h+r)

=2×22/7×0.025(28+0.025)m^2

=44×0.025×28.025/7m^2

=4.4m^2