In a hot water heating system, there is a cylindrical piping of length 32.5 m and diameter 5 m. Find the total radiating surface in the system.
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Answer:
The cylindrical pipe radiates from the curved surface & not from the ends
The cylindrical pipe radiates from the curved surface & not from the endsSo, we need to find curved surface area of cylinder
The cylindrical pipe radiates from the curved surface & not from the endsSo, we need to find curved surface area of cylinderHeight (h) of cylindrical pipe = = 28 m
The cylindrical pipe radiates from the curved surface & not from the endsSo, we need to find curved surface area of cylinderHeight (h) of cylindrical pipe = = 28 m5 Radius (r) of circular end of pipe = cm = 2.5 cm 2
The cylindrical pipe radiates from the curved surface & not from the endsSo, we need to find curved surface area of cylinderHeight (h) of cylindrical pipe = = 28 m5 Radius (r) of circular end of pipe = cm = 2.5 cm 2r= 2.5 x 1 100 m = 0.025 m
The cylindrical pipe radiates from the curved surface & not from the endsSo, we need to find curved surface area of cylinderHeight (h) of cylindrical pipe = = 28 m5 Radius (r) of circular end of pipe = cm = 2.5 cm 2r= 2.5 x 1 100 m = 0.025 mTotal radiating surface in the system = CSA of cylindrical pipe
The cylindrical pipe radiates from the curved surface & not from the endsSo, we need to find curved surface area of cylinderHeight (h) of cylindrical pipe = = 28 m5 Radius (r) of circular end of pipe = cm = 2.5 cm 2r= 2.5 x 1 100 m = 0.025 mTotal radiating surface in the system = CSA of cylindrical pipe= 2nrh
The cylindrical pipe radiates from the curved surface & not from the endsSo, we need to find curved surface area of cylinderHeight (h) of cylindrical pipe = = 28 m5 Radius (r) of circular end of pipe = cm = 2.5 cm 2r= 2.5 x 1 100 m = 0.025 mTotal radiating surface in the system = CSA of cylindrical pipe= 2nrh= (2 x 2 x 0.025 x 28) m? 7
The cylindrical pipe radiates from the curved surface & not from the endsSo, we need to find curved surface area of cylinderHeight (h) of cylindrical pipe = = 28 m5 Radius (r) of circular end of pipe = cm = 2.5 cm 2r= 2.5 x 1 100 m = 0.025 mTotal radiating surface in the system = CSA of cylindrical pipe= 2nrh= (2 x 2 x 0.025 x 28) m? 7= 4.4 m?