Question

In a hotel 60% had vegetarian lunch while 30% had non vegetarian lunch and 15% has both type of lunch. If 96 people were present, how many did not eat either type of lunch

Answer 1

let total be 100%

given 15 % will eat both types

also given 60% veg so only veg people 60-15= 45%

30% non-veg so only non-veg 30-15= 15%

so total 45+15+15= 75% are eating

out of 100% only 75% are eating so remaining 25% are not eating

given 96 people

25% of 96 people

25% can be written as 1/4

96*1/4= 24 people were not eating both

Answer 2

There are 25% who did not eat either type of lunch.

Step-by-step explanation:

Since we have given that

Percentage of vegetarian = 60%

Percentage of non vegetarian = 30%

Percentage of both type = 15%

So, P(V∪N)=P(V)+P(n)-P(V∩N)

$=60+30-15\\\\=90-15\\\\=75\%$

So, Percentage that did not eat either type of lunch is given by

$100\%-75\%\\\\=25\%$

Hence, there are 25% who did not eat either type of lunch.

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In a hotel 60% had vegetarian lunch while 30% had non vegetarian lunch and 15% has both type of lunch. If 96 people were present, how many did not eat either type of lunch

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