Math, asked by rajarohit780, 10 months ago

In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and

15% had both type of lunch. If 96 people were present, how many did not eat

either type of lunch​

Answers

Answered by dadasirsat82
0

Answer:

105

Step-by-step explanation:

105 =60 +30+15

=105

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