In a hotel, 60% has vegetarian lunch while 30% had non-vegetarian lunch and 15% had both types of lunch, if 96 people were present, how many did not eat either type of lunch?
Answers
Answered by
0
1% was not have their lunch because
60+30+15 = 95
Similar questions
Math,
5 months ago
English,
5 months ago
Math,
5 months ago
Social Sciences,
10 months ago
Math,
10 months ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago