In a house 10 bulbs of 100 watt each, 5 fans of 80 watt each,a refrigerator of 300 watt and a heater of 1 KW is used.Bulbs and fans are used 10 hrs. per day, refrigerator used24 hrs. and heater used 2 hrs. per day. Find the cost of electric at the rate of Rs. 5 for 1 month
Answers
Answer:
Total Energy consumed is 108.5 Kwh and Cost is Rs 390.6
We Have :-
3 bulbs of 100 watt each lighted for 5 hours daily
2 fans of 50 watt each used for 10 hours daily
Electric heater of 1.00 kW used for an hour daily
Rate of 3.60 per Kwh
To Find :-
Total Energy consumed in a month of 31 days and Cost
Formula Used :-
Energy consumed = Power × time
Solution :-
Energy consumed by Bulbs :-
Power = 3 * 100 watt = 300 watt = 0.3 Kw
Time = 5 hours in one day
= 5 * 31 in a month
= 155 hours
Energy = 0.3 * 155
= 46.5 Kwh
Energy consumed by Fans :-
Power = 2 * 50 = 100 watt = 0.1 Kw
Time = 10 hours in one day
= 10 * 31 in a month
= 310 hours
Energy = 0.1 * 310
= 31 Kwh
Energy consumed by Heater :-
Power = 1 Kw
Time = 1 hours in one day
= 1 * 31 in a month
= 31 hours
Energy = 1 * 31
= 31 Kwh
Total Energy consumed = 46.5 + 31 + 31
= 108.5 Kwh
Cost :-
1 Kwh = Rs 3.60
108.5 Kwh = Rs 3.60 * 108.5
= Rs 390.6
Total Energy consumed is 108.5 Kwh and Cost is Rs 390.6