Question

In a house, 2 bulbs of 50W each are used for 5 hours a day and two 70W each, fans are used 10 hours a day. Calculate the units consumed in a month of 30 days.

Answer 1

For 1 bulb energy consumed is 50w and time is 5 hrs so :-
50x5= 250wh
And for 2 bulb it is 250x2=500wh
For 1 fan energy consumed is 70w
And time is 10 hrs so:-
70x10=700wh
And for 2 fans it is 700x2=1400wh
And if we calculate it for 30days of both bulb and fan it will be
1400+500×30=57000wh

Answer 2

Answer:

In a house, 2 bulbs of 50W each are used for 5 hours a day and two 70W each, fans are used 10 hours a day, the units consumed in a month of 30 days is 57KW

Explanation:

The number of bulbs  $=2$

power used by one tube light $=50W$

working time of tube light in a day $=5hrs$

total power consumption of tube light in a month $=30*5*50*2=15000W$

The number of fans $=2$

power used by one fan $=70W$

working time of a fan in a day $=10hrs$

total power consumption of the fan  $=30*10*70*2=42000W$

so the total power consumption of the home $=15000+42000=57000W=57KW$