Physics, asked by talithasimon20, 10 months ago

In a house, 3 bulbs of 100 watt each are lighted for 5 hours daily, 2 fans of 50 watt each are used for 10 hours daily and an electric heater of 1kWh is used for half an hour daily. Calculate the total energy consumed in a month of 31 days and its cost at the rate of ₹ 3.60/kWh

Answers

Answered by suhassubramani2811
12

Explanation:

Total Energy consumed is 108.5 Kwh and Cost is Rs 390.6

Explanation:

We Have :-

3 bulbs of 100 watt each lighted for 5 hours daily

2 fans of 50 watt each used for 10 hours daily

Electric heater of 1.00 kW used for an hour daily

Rate of 3.60 per Kwh

To Find :-

Total Energy consumed in a month of 31 days and Cost

Formula Used :-

Energy consumed = Power × time

Solution :-

Energy consumed by Bulbs :-

Power = 3 * 100 watt = 300 watt = 0.3 Kw

Time = 5 hours in one day

       = 5 * 31 in a month

       = 155 hours

Energy = 0.3 * 155

           =  46.5 Kwh

Energy consumed by Fans :-

Power = 2 * 50 = 100 watt = 0.1 Kw

Time = 10 hours in one day

       = 10 * 31 in a month

       = 310 hours

Energy = 0.1 * 310

           = 31 Kwh

Energy consumed by Heater :-

Power = 1 Kw

Time = 1 hours in one day

       = 1 * 31 in a month

       = 31 hours

Energy = 1 * 31

           = 31 Kwh

Total Energy consumed = 46.5 + 31 + 31

                                      = 108.5 Kwh

Cost :-

1 Kwh = Rs 3.60

108.5 Kwh = Rs 3.60 * 108.5

                = Rs 390.6

Total Energy consumed is 108.5 Kwh and Cost is Rs 390.6

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