Question

In a house 3 bulbs of 100 watt each lighted for 5 hours daily, 2 fans of 50 watt each used
for 10 hours daily and an electric heater of 100 kW is used for an hour daily. Calculate the
total energy consumed in a month of 31 days and its cost at the rate of 3.60 per kWh.​

Answer 1

Answer:

3bulb of 100 w for 5 hrs.

3 ×100×5 = 1500 w = 3/2 kwh

2 × 50 × 10 = 1000 w = 1 kwh.

100 kw × 1 hr = 100kwh.

for 31 days.

3/2 × 31 = 93/2

1 × 31 = 31

100 × 31 = 3100 .

now adding these

93/2 + 62/2 +6200/2  = 6355/2.

= 2177.5

now cost is 2177.5 × 3.6

= 7838 rupees

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Answer 2

Answer:

I have attached the answer.. hope it helps you