Question

In a house 3 bulbs of 100 watt each lighted for 5 hours daily, 2 fans of 50 watt each used
for 10 hours daily and an electric heater of 100 kW is used for an hour daily. Calculate the
total energy consumed in a month of 31 days and its cost at the rate of 3.60 per kWh.​

Answer 1

Answer:

ANSWER IS rs. 352.8

Explanation:

3 bulb of 100 w for 5 hrs.

3 ×100×5 = 1500 w = 3/2 kwh

2 fans of 50 watt for 10 hours

2 × 50 × 10 = 1000 w = 1 kwh.

electric heater of 1.00 kW for half an hour

1 kwh × 1/2 hr = 1/2 kwh.

so for 31 days--

3/2 × 31 = 93/2

1 × 31 = 31

1/2 × 31 = 31 / 2.

now adding these

93/2 + 31/2 + 62/2 = 196/2.

= 98Kwh

now cost is 98 × 3.6

= rs. 352.8