in a house 3 bulbs of 50w each are used for 4hrs a day. and 3 fans of 60w are used 10hrs a day . calculate the unit of electricity consumed in a month of 30 days?
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Power consumed by 3 bulbs = 3 x 50w = 150 w = 0.150 x 4 = 0.6 Kwh
power consumed by 3 fans = 3 x 60 = 180 w = 0.180 x 4 = 0.72 Kwh
adding both we get = 1.32 Kwh
in 30 days the power = 1.32 x 30 = 39.6 Kwh or units
In 30 days the unit of electricity consumed = 40 (approx)
power consumed by 3 fans = 3 x 60 = 180 w = 0.180 x 4 = 0.72 Kwh
adding both we get = 1.32 Kwh
in 30 days the power = 1.32 x 30 = 39.6 Kwh or units
In 30 days the unit of electricity consumed = 40 (approx)
sabarinathcs:
hope this help
Answered by
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Solution:
3 bulbs of 100 w for 5 hours
3 X 300 = 1500 W = 3/2 KWH
2 X 50 X 10 = 1000 W = 1 kWh
100 k X 1 hr = 100 kwh
then let's calculate for 31 days,
3/2 X 31 = 93/2
1 X 31 = 31
100 X 31 = 3100
now add these all
93/2 + 62/2 + 6200/2 = 6355/2
=2177.5
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