Question

in a house 4 electric bulbs of 40 watts burn for 5 hours, 2 bulbs of 60 watts for 6 hours and 3 fans of 80 watts for 6 hours, daily. What would be the cost of electricity, for one month of that home, if the Rate is 50 paise per unit? (Rs 44.4)​

Answer 1

Answer:

bulb rating=40watt=0.4kw

bulb illuminates for=10hrs/day

bulb consumes units(kwh)/day=0.4×10=.4kwh/day=.4units/day

In 30 days =.4×30=12units

1 unit cost=250/-

12 units cost=250 ×12=3000

Answer 2

Given:

4 bulbs of 40W burn for 5hrs.

2 bulbs of 60W burn for 6hrs.

3 fans of 80W worked for 6hrs.

To find: cost of electricity for 1 month.

Step-by-step method:

Step 1 of 2

The power consumption is calculated by multiplying the power with the time of its working.

energy consumption(kWh)= Power (in Watts) x Hours of operation/1000

Energy consumption-

4 electric bulbs= $4*\frac{40*5}{1000} =0.8kWh$

2 bulbs = $2*\frac{60*6}{1000} =0.72kWh$

3 fans = $3*\frac{80*6}{1000} =1.44kWh$

Step 2 of 2

For one day the energy consumption is 0.8+0.72+1.44=2.96kWh

For one month the energy consumption will be 2.96x30=88.8kWh

Cost of electricity is 0.5x88.8=Rs.44.4     (50 paise =0.5Rs)

COST OF ELECTRICITY IS Rs.44.4