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In a house 4 lamps of 100 W and 2 fans of 160 W run for 5 hours a day. If the cost of one unit of electricity
is Rs. 10, then calculate the total cost of electricity for a month.
Answers
Answer:
Units consumed in lamps = 4[100*5/1000] kWh
= 2 kWh
Units consumed in fans = 2[160*5/1000] kWh
= 1.6 kWh
Total units consumed in a day = [2+1.6] kWh
= 3.6 kWh
Total units consumed in a month = 3.6*30 kWh
= 108 kWh
If cost of 1 kWh is Rs. 10, then, the total cost of electricity at the end of the month will be = Rs. (108*10)
Rs. 1080
Hope This Helps.
Given:-
- Power of Lamp ,P = 100W
- Number of Lamp = 4
- Power of Fans ,P' = 160 W
- Number of fans = 2
- Cost of one Unit = Rs 10
To Find:-
- The total cost of electricity for a month.
Solution:-
There are 30 days in a month.
Power of 4 lamps = 4×100 = 400 W
•E = Pt
where
E is the energy consumed
P is the power
t is the time taken
Substitute the value we get
→ E = 400×5
→ E = 2000 Kw
→ E = 2000/1000 kWh = 2 kWh or 2 unit
Power of 2 fan = 2×160 = 320 W
• E' = Pt
Substitute the value we get
→ E' = 320×5
→ E' = 1600kW
→ E' = 1600/1000 kWh = 1.6 kWh or 1.6 Unit
Total energy consumed by appliances = 2+1.6 = 3.6 Unit
Now,
Energy Consumed by appliances in 30 days = 30 × 3.6 = 3× 36 = 108 Unit
→ Cost of 1 Unit = Rs 10
Therefore , Cost of 108 Unit = 108
8×10 = Rs1080
Therefore , Total cost of electricity for a month is Rs.1080 .