Question

in a house by tubelight of 40 w is used for 5 hours and an electrical iron of 500 w 4 hours everyday calculate the electrical energy consumed by these appliances in a month of 30 days​

Answer 1

Answer:

66kwh

Explanation:

for tube light..

Power = 40 w = 0.04 kw

time = 5 hours

E= P x t

E = 0.04 x 5 = 0.2kwh

E for 30 days = 30 x 0.2 = 6kwh. .......( i )

for iron..

Power = 500 w = 0.5 kw

time = 4 hours

E= P x t

E = 0.5 x 4 = 2 kwh

E for 30 days = 30 x 2 = 60 kwh. .......( ii )

soo...

Total Electric Energy = 6kwh +60kwh = 66kwh