Question

In a house there are : 1 T.V unit of power 1200 watt which runs for 10 hr , 1 fridge of power 600 watt which runs for 20 hr , 2 fans of power 200 watt each runs for 20 hr a day . If a cost of 1 kWr is rupees 10 then calculate the bill of the house in the month of April.​

Answer 1

Answer:

The total bill of the house in the month of April is 9600 Rs.

Explanation:

Energy consumed by T.V per day;

$E_{T.V}=1200 \text{ W}\times10\text{ hr}\\=12000\text{ Wh}\\=12\text{ kWh}$

Energy consumed by fridge per dat;

$E_{fridge}=600\text{ W}\times20\text{ hr}\\=12000\text{ Wh}\\=12 \text{ kWh}$

Energy consumed by fans per day;

$E_{fans}=2\times200\text{ W}\times20\text{ hr}\\=8000\text{ Wh}\\=8\text{ kWh}$

Energy consumed per day;

$E=E_{T.V}+E_{fridge}+E_{fans}\\=12\text{ kWh}+12\text{ kWh}+8\text{ kWh}\\=32\text{ kWh}$

Total energy consumed in the month of April:

$E_{total}=E\times\text{number of days in april}\\=32\text{ kWh}\times30\\=960\text{ kWh}$

The bill is given as;

$\text{amount to be paid}=E_{total}\times\text{Rate}\\=960\text{ kWh}\times10\text{ Rs./kWh}\\=9600\text{ Rs.}$