Physics, asked by apmariyammal148, 11 months ago

in a house total load consists of 5 lamps of 40w, 2 fans of 75 w each, 1 refrigerator of 800w, 1 washing machine of 950w and 1 air conditioner of 1500w.if the supply is 230v then for an average loading of 50% through the day energy consumed in 24 hrs in Fundamentals of Electrical Engineering

Answers

Answered by amitnrw
7

Answer:

43.2 Units

Explanation:

In a house total load consists of 5 lamps of 40w, 2 fans of 75 w each, 1 refrigerator of 800w, 1 washing machine of 950w and 1 air conditioner of 1500w.if the supply is 230v then for an average loading of 50% through the day energy consumed in 24 hrs

Total Load = 5 * 40  +  2*75  + 1*800  + 1 * 950  +  1* 1500

= 200 + 150 + 800 + 950 + 1500

= 3600 W

= 3.6 kW

Unit consumed in 1hr with 50 % loading = 0.5 * 3.6kw *1 = 1.8 kwh = 1.8 unit

Units consumed in 24 hrs = 24 * 1.8 = 43.2 Units

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