Question

in a house two 60 with electric bulbs are lighted for 4 hours , and three 100 with bulbs for 5 hours everyday . calculate the electric energy consumed in 30 days .​

Answer 1

Answer:

59.45 kwh

Explanation:

bulb 1

kwh=(n x p x t)/1000

n=2

p=60 w

t=4 h

kwh=(2 x 60 x 4)/1000=.48 kwh

bulb 2

kwh=(n x p x t )/1000

n=3

p=l00w

t= 5 h

kwh=(3 x 100 x 5)/1000

kwh= 1.5 kwh

energy consumed in 1 month = .(48+1.5) x 30=1.98 x 30=59.45 kWh