Question

in a house two 60W electric bulbs are lighted for 4 hours and three 100W bulbsfor 5 hours everyday calculate the electric energy consumed in 30 days​

Answer 1

Explanation:

$\boxed{GIVEN}$

• in a house two 60w bulb are lighted for 4hour

The electric enery consumed in 1 day is

$energy = power \times time \: taken$

$energy = 60w \times 4hour \times 2$

$energy = 480joule$

now

• three bulbs of 100w is lighted for 5hours

the electrical energy consumed is

$energy = 100w \times 5hour \times 3$

$energy = 1500joule$

the total electrical energy consumed in 1 day

$\boxed{1500+480=1980joule}$

The electrical energy consumed in 30day

$energy = 1980joule \times30days$

$\boxed{59,400joule}$

Answer 2

Answer:There are two 60W bulbs.

Total P=60×2=120w

Time=4h

Energy consumed=power×time

=120×4

=480wh.

:There are three 100w bulbs

Total P=100×3=300w

Time=5h

Energy consumed=Power×time

=300×5

=1500wh.

:Total power=1500+480=1980wh

Energy consumed in 30 days

=30×1980

=59400wh

=59.4kwh

Explanation: