Question

In A Hunting Camp There Were Dogs And Men.If There Were Altogether 11 Head And 38 Legs,How Many Dogs Were There?

Answer 1

Answer:

According to me there are 4 dogs

Answer 2

Answer:

There were 8 dogs.

Explanation:

Given data and assumptions :

Let the number of dogs and men be x and y.

Total number of heads = 11

Total number of legs = 38

Forming equations :

Since there were 11 heads,then

x+y = 11 .....equation (1)

Dogs have 4 legs and humans have 2 legs,then

4x + 2y = 38 ......equation(2)

Solving to get results :

Multiplying equation (1) by 2 , we get :

2x + 2y = 22 .....equation (3)

Now, Subtracting (3) from (2) , we get :

$2x = 16 \\ x = \frac{16}{2} = 8$

Putting x = 8 in equation(1) , we get

y = 3

Hence, there were 8 dogs.

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