Question

In a hurdle race among rita,seeta and geeta.Rita cleared 4 hurdles,Sita 1/2(half) of all hurdles whereas Geeta could clear only 2/3 of all hurdles.If there are a total of twelve hurdles on the trade.Who cleared more and who cleared minimum hurdles
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Answer 1

Answer:

ANSWER

Let X denote the number of hurdles knocked down by the player. Then, X follows binomial distribution with 

n=10,p=1−65=61 and q=65.

Therefore,

P(X=r)=10Cr(61)r(65)10−r,r=0,1,2,...,10

Required probability = P(X<2)=P(X=0)+P(X=1)

=(65)10+10C1×61×(65)9=2×69510

hope it helps you