Question

in a hurdle race among Rita Sita and Geeta Rita cleared for hurdle Sita one by two of all hurdles when was Geeta could clear only 2 by 3 of all hurdles if there are a total of 12 handles on the track who cleared maximum hurdles clearly and who cleared minimum hurdle​​

Answer 1

answer

Geeta cleared maxim hurdles and Rita cleared minimum hurdles

Step-by-step explanation:

Rita clearead four hurdles out of 12

sita cleared one by two hurdles means 1/2*12=6hurdles

while Geeta cleared 2 by3 hurdles means 2/3*12=8hurdles

Rita 4

sita 6

geeta 8

4<6<8