In a hydraulic jack, the small piston (A) has an area of 0.1 meters squared and the large piston has an area of 20 meters square.
If a mechanic pushes on Piston A with a force of 200N, what will be the pressure? show your working.
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Hydraulic lift works on the principle of pascal's law
P=a1F1=a2F2
applying the given formula to the question.
0.901.2×104=0.2FF=0.900.24×104=2.67×103N
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